What Happens to the Wave Function When the Size of a Quantum Well Doubles?

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Homework Statement



there is a infinite quantum well with size L and there is a particle in it with mass m. suddenly the size of the quantum well is doubled. What will be the wave function at a later time t ?

Homework Equations



ψ= \sqrt{2/L} sin (n pi x / L)

E = n^2 pi^2 h^2 / 2mL^2

The Attempt at a Solution



do we need to find cn again with 2L ?
 
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Yes.
I'd normally do this by expressing the initial state of the particle, in the 1L well, in terms of a superposition of states of the final 2L well... then finding the time-evolution of those states.

I'd have expected the initial state to be a specified n state (i.e. the ground state).

A lot depends on context - eg.
If there is a mechanism for decay present, then the question could be answered in terms of the energy lost in the decay from initial to final states. (Otherwise the system remains in a composite state until some measurement of energy is made.)
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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