1. The problem statement, all variables and given/known data What happens when you place a NOT gate before and after a NAND gate 2. Relevant equations Current Research(My own work): NOT Gate: A NOT gate is also known as an inverter. It is a logic gate which implements a methodology best known in maths as Logical Negation. In other words a NOT gate takes whatever results that are passed through it, usually True or False(0 or 1) and negates them. A NOT gate only requires one value. AND Gate: An AND gate is a logic gate which implements a methodolgy best known as logical conjunction. The logical conjunction linked with an AND gate appears when both values are true, thus returning the value of true. All other values return false. An AND gate requires 2 values to produce an output. NAND Gate: A NAND gate follows the same principles as the afforementioned AND gate. However its results are effect by a NOT gate. According to the material above, a NOT gate negates values and an AND gate only returns true if both values are true. Using this we can deduce that the output of a NAND gate will be the exact opposite to those of an AND. 3. The attempt at a solution Default NAND Gate: INPUT A B OUTPUT 0 0 1 0 1 1 1 0 1 1 1 0 Now a NOT gate placed infront of a NAND gate would invert the values being passed through it, but not the output. (This is where i start to get a little confused) NOT NAND Gate: INPUT A B OUTPUT 1 1 1 1 0 1 0 1 1 0 0 0 Which is equal to an OR gate. (But im not sure why?) NAND NOT Gate: INPUT A B OUTPUT 0 0 0 0 1 0 1 0 0 1 1 1 Which is equal to an AND gate. Which kind of makes sense to me because if you put a negative and a negative together you get positive but once again im not exactly sure. Thanks in advance for any help, i appreciate it.