What Height Was the Baseball Dropped From Based on Its Momentum?

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A .150 kg baseball is dropped from rest, and its momentum just before landing is .780 kg m/s. To find the height from which it was dropped, the final velocity can be calculated using the momentum equation P=mv. The acceleration due to gravity is 9.81 m/s², which simplifies the problem. By applying energy balance principles, the correct height can be determined without needing time. The discussion concludes with a confirmation of the correct solution.
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Homework Statement


A .150kg baseball is dropped from rest. IF the magnitude of the baseball's momentum is .780 kg m/s just before it lands on the ground, from what height was it dropped?


Homework Equations



P=mv

The Attempt at a Solution



I found the final velocity and know that the inital position is zero and the initial velocity is zero obviously. i tried to go back to the kinematic equations to solve for final position but i do not know time and i do not know acceleration.
 
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Use an energy balance and choose you title with care please...
 
energy balance?
 
Hi alyson42,

alyson42 said:

Homework Statement


A .150kg baseball is dropped from rest. IF the magnitude of the baseball's momentum is .780 kg m/s just before it lands on the ground, from what height was it dropped?


Homework Equations



P=mv

The Attempt at a Solution



I found the final velocity and know that the inital position is zero and the initial velocity is zero obviously. i tried to go back to the kinematic equations to solve for final position but i do not know time and i do not know acceleration.

You don't know the time, but are you sure you don't know the acceleration?
 
acceleration due to gravity? just 9.81 m/s? can it be that easy?
 
Sounds good; your acceleration units aren't quite right, but maybe that's just a typo. Depending on how you set up the problem you might need to be careful with signs, but it seems to be a straightforward problem.
 
i got the correct answer. You are a genius. Thanks for the help!
 
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