# What if capasitor plate in different size

## Main Question or Discussion Point

hi..
cant set both site fit face face.. ( not meaning paralel)
if make one side I mean plate much bigger.. and athor plate respectivel small (whic calculated area..) ..
So what happens.. I think I could use small one while callculating Area.. ?
2. if I am not iright is there any mistake approxamation..error rate
3. and would it bigger then my fit error ..while trying to put equal plate face to face instead above..
thnx..

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hi..
cant set both site fit face face.. ( not meaning paralel)
if make one side I mean plate much bigger.. and athor plate respectivel small (whic calculated area..) ..
So what happens.. I think I could use small one while callculating Area.. ?
2. if I am not iright is there any mistake approxamation..error rate
3. and would it bigger then my fit error ..while trying to put equal plate face to face instead above..
thnx..
I'm not sure what you are asking? Are you asking whether you can use plates that aren't parallel and so are at some angle to each other?

If you did this then you would end up with a lower capacitance than if they were parallel. If one plate was larger than the other, then the area wouldn't change, as the area refers to the area which is parallel to the other, so you would only have the area of the small plate available.

there is no problem being paralel.. as I mentioned above..
are you answering due to some teorotical calculation.. or experimantal value..
between plates I am usign ceramics.. so one side bigger ..other side smaller.. and doest affect any dielectric mesaurment .. electrical measurement??
am I right.. cp values are around 10E-12 ..
so am I doing it right? have no time to test it.. I am just looking.. that is tested..

Gold Member
C = $$\frac{\epsilon A}{d}$$
Where;
C is capacitance
$$\epsilon$$ is the permittivity
A is the *parallel* area
d is the distance between the plates

So it doesn't matter how large the plate is, both plates need to be big if you want C to be big.

* The top is not working, it should be $$\epsilon$$ * A

I am not having problem to make plates big.. I know what the formule is..
just asking plate size different ..
so pls read above more detailed ..
thnx..

two plae is not identical (they are paralell.. their areas are different.) .. and so what happens..?

uart
For your sake mentatx I sure hope that English isn't your first language!

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Gold Member
I'm not sure if I understand exactly what you’re asking?

I'm not sure if I understand exactly what you’re asking?
[URL]http://www.physics.sjsu.edu/becker/physics51/images/25_02ParallelPlateCap.JPG[/URL]

I think he wants to know how capacitance would be effected if, for example, the top plate had an area 2A.

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yeap.. that is it..
and if it is.. what is the error rate...
and.. is there any searh about it.. any calculted data.. I am looking for erron about 10E-15
thnx..

and .. I know what I am using... I mean language.. the reason is.. I want answer from cabaple person..

no one... ??