What Is Stability in the Context of the Hill Equation for a Mass-Spring System?

Drokz
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When trying to solve a problem I arrive at the following equation of motion / Hill equation:

\frac{d^{2}y}{dx^2} + \frac{4 k_0}{m w^2} cos(2x)y = 0

There exists a value x_0 such that for all x>x_0 the motion is stable.

I actually don't know what is meant by this 'stability'. Can someone help, please?

Thanks, Drokz
 
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I've usually seen Hill's equation with omega^2, not omega^(-2). Is this a typo?
 
I don't think it is a typo. Omega is just a constant here, I think.
 
Ok. Solutions are products of exponential terms and periodic functions, so your stability condition is needed to keep the exponential parts of the solutions bounded. Do you have access to a reference on Mathieu functions like Whittaker and Watson, or Erdelyi's Higher Transcendental Functions? The latter one has a clear discussion of the stable and unstable solution regions (p. 101 vol. 3).
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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