What is the acceleration of a bullet passing through a board?

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To find the bullet's acceleration as it passes through a 14.0 cm thick board, the initial speed is 450 m/s and the final speed is 220 m/s. The formula v² = u² + 2as can be used, where s is the distance (converted to meters), u is the initial speed, v is the final speed, and a is the acceleration. Participants emphasize the importance of showing work in homework discussions and note that direct answers cannot be provided. The conversation highlights the need for understanding the physics principles involved in calculating acceleration.
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Hello, please any help will be very much appreciated;

A bullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s, what is the bullet's acceleration as it passes through the board?
 
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Hi there, this belongs in the homework section.

Jared
 
Using: v2 = u2 + 2as

Where s = distance, u = initial speed, v = final speed and a = acceleration.

You know s, u and v. Plug them in and rearrange to give an answer for a.

Don't forget to convert cm to m.

We cannot give you direct answers as per the guidelines, but we can help, however in future you must show your attempt.

Jared
 
Oh thanks very much...
 

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