What is the acceleration of an object with two given forces acting on it?

AI Thread Summary
The discussion revolves around calculating the acceleration of a 3.00 kg object subjected to two forces: F1 at 60.0 N at a 45-degree angle and F2 at 40.0 N along the +x axis. The calculations yield a vertical force component (Fy) of 42.4 N and a horizontal force component (Fx) of 42.4 N from F1, while F2 contributes 40.0 N horizontally. The resulting acceleration in the y-direction (ay) is calculated to be 34.13 m/s², and in the x-direction (ax) is 13.3 m/s². The total acceleration magnitude is found to be 36.6 m/s², directed at an angle of 68.7 degrees above the +x axis. The user resolves their confusion regarding the calculation of ax, confirming the final results.
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Homework Statement

Only two forces act on an object (mass=3.00kg). F1=60.0N 45.0deg above the +x axis, F2=40.0N on the +x axis. Find the magnitude and direction (relative to the x axis) of the acceleration of the object.




Homework Equations


F=ma,



The Attempt at a Solution


(60.0N)(sin(45))=Fy, Fy=42.4N
(60.0N)(cos(45))=Fx, Fx=42.4N
ay=((60.0N)+(42.4N))/3.00kg
ay=34.13 m/s^2
ax=40.0N/3.00kg
ax=13.3 m/s^2
a=36.6 m/s^2
68.7 deg above +x axis

I can't figure out where I am going wrong.
 
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ax=40.0N/3.00kg
ax=13.3 m/s^2
I think here.
 
ax is wrong?
 
nevermind I got it.
 
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