What is the acceleration of the cart down the incline?

AI Thread Summary
The discussion revolves around calculating the acceleration of a cart down an incline using the slope of a graph plotted from time and distance data. The slope of the graph, given as 15 cm/s², directly relates to the acceleration based on the kinematic equation s = ut + (1/2)at². Since the initial velocity is zero, the formula simplifies to show that the slope represents half the acceleration. Therefore, the acceleration of the cart can be determined by doubling the slope value, resulting in an acceleration of 30 cm/s². The conversation also notes a concern about the appropriateness of the topic's placement in the forum.
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Question: Suppose you have measured the time (delta T) required for a glider to travel several distances (delta X) down an inclined plane. After plotting the data points on a graph of delta X vs. (delta T)^2, you find the slope of the best fitting straight line is 15cm/s^2. What is the acceleration of the cart down the incline?

I am have such difficulty trying to figure out where to start with this problem. I know that slope = rise/run and that Acceleration = the limit of delta V/ delta T, as T goes to zero. If someone could please point me in the right direction to figuring it out, it would be greatly appreciated!
 
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Do you know the relationship between distance traveled and time under constant acceleration. Ther is a basic kinematics equation here :

s = ut + \frac{1}{2}at^2 where s is the distance travelled, u is the initial velocity, a is the (constant) acceleration and t is the time elapsed.

For your problem, you can let the initial velocity be zero (the glider starts at rest). Use the equation to figure out how the acceleration relates to the gradient of the straight line obtained by plotting s vs t^2.
 
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BTW, I'm fairly certain this doesn't belong in the College section.
 
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