What Is the Angle Between Velocity Vector and Trajectory at Maximum Height?

AI Thread Summary
At maximum height, the vertical component of a projectile's velocity becomes zero, while the horizontal component remains constant. This results in the angle between the velocity vector and the trajectory being zero degrees. The initial velocity of the projectile is given as 150 m/s, and the relevant equations for projectile motion confirm this relationship. Therefore, the correct answer to the question posed is that the angle is zero degrees. Understanding this concept is crucial for solving projectile motion problems effectively.
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Homework Statement



the initial velocity of a projectile is 150 m\s .the angle between the velocity vector and the trajectory at the projectile's maximum height is
a) 90
b) 45
c) zero
d) 63.1
e) 36.9

Homework Equations



Vox= vx = Vocosθ
Vy = Vosinθ-gt
Range (R) = (vo)^2*sin(2θ)/g
Maximum Height (H) = (vo)^2*(sinθ)^2/2g

The Attempt at a Solution



http://im40.gulfup.com/43qMA.jpg

in this image we can see that the angle at the maximum height is 0 but I want to get sure ?
 
Last edited by a moderator:
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Correct.
 
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