What is the angle Θ in the equation for magnetic field force?

[pyroknife]

Right now I'm looking at this equation for magnetic field force where F=BqVsinΘ where B is magnetic field, q is charge of particle, and V is velocity. However I've seen from some sites that F does not include sinΘ so I was confused on whether which one is right. And also what is Θ in respect to. Is it the angle of the particle direction to the magnetic field?

 

[buffordboy23]

This is the vector form of the equation for the force on a charged-particle with some velocity in a magnetic field:

\vec{F} = q\vec{v}\times\vec{B}

If your given the velocity and the magnetic field in vector form, i.e. \vec{v} = \left(v_{x}\right)\hat{x} + \left(v_{y}\right)\hat{y} + \left(v_{z}\right)\hat{z}, then you can determine the force vector by taking the cross-product. Clear?

Using just magnitudes of the quantities gives the second-form:

F = qvBsin\theta

where \theta is the angle between the velocity, v, and the magnetic field B. This form is used quite often when v and B are constants. Now, if \theta = \pi/2 then the sine term has value 1, so when you do not see the sine term this is what you should assume. Clear?