The discussion revolves around approximating the value of the function f(x) = aln(x+2) at x = 0.98 using Euler's method. Participants are exploring the implications of the derivative f'(1) = a/3 and the lack of a specified increment interval for the calculation.
Some participants have provided feedback on the original poster's approach, suggesting a possible correction in the expression used. There is an ongoing exploration of the multiple-choice options available, with participants noting that none of the choices match the original calculation involving aln(3).
Participants are working under the constraint of not having a specified increment interval, which is leading to assumptions in their calculations. The presence of multiple-choice answers adds complexity to the discussion, as participants question their relevance to the original problem.
daivinhtran said:Homework Statement
consider the function f(x) = aln(x+2). Given that f'(1) = a/3, what is the approximate value of f(0.98)?
Homework Equations
f(x1) = f(x0) + f'(x0)x(x1-x0)
The Attempt at a Solution
I solved it and get
f(.98) = aln(1+2) + (.098-1) = aln(3) - (.02)(a/3) <= not an answer
the bad thing is my teacher don't give me the increment interval. ..So I assumed it is .02
Dick said:That seems all right. Though you probably mean (0.98-1)(a/3) in you solution. Does 'not an answer' mean this is multiple choice? If so what are the possible answers?
daivinhtran said:A. (0.98-1)(a/3) + aln(2.98)
B. (a/3)aln(2.98) + .98
C. -.02a/3
D. (.98)ln(a/3)
E. (a/3) (.98) + aln(2.98)
none of them has aln3 like I solved