What Is the Atomic Mass of Element A with Given Isotopes and Abundances?

AI Thread Summary
To find the atomic mass of element A, the isotopes and their abundances must be used in the weighted average formula. The isotopes provided are 86A with an atomic mass of 85.909 u and an abundance of 16.19%, 87A with an atomic mass of 86.908 u and an abundance of 7.00%, and 88A with an unknown abundance calculated as 76.81%. The equation for the atomic mass is (85.909 x 0.1619) + (86.908 x 0.07) + (87.906 x 0.7681). By plugging in these values, the atomic mass of element A can be determined for the periodic table.
CMATT
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Homework Statement


Suppose the element A contains three isotopes, 86A (atomic mass 85.909 u, abundance 16.19%) 87A (atomic mass 86.908, abundance 7.00%) and 88A (atomic mass 87.906 u). What would be the atomic mass of A that would appear in the periodic table?

Homework Equations


(A1 x %A1) + (A2 x %A2) + (A3 x (1-(%1 +%2)) = answer

The Attempt at a Solution



16.19% + 7.00% = 23.19%

100% - 23.19% = 76.81% --> so that would be the 88A abundance % right?

then I'm confused from there. Please help
 
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CMATT said:
100% - 23.19% = 76.81% --> so that would be the 88A abundance % right?
Sure.
CMATT said:
then I'm confused from there. Please help
Just plug everything into the equation you have.
 
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