What is the Average Force Exerted on Occupants by Seatbelts in a Car Collision?

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The average force exerted on occupants by seatbelts during a car collision can be calculated using the formula f=ma. For an 80 kg man in a car moving at 75 kph, the calculated force is approximately 8333.3 Newtons, based on a collision duration of 0.2 seconds. The weight of the car does not affect the force experienced by the occupants in this context. The discussion highlights confusion around the calculations but confirms the correct application of the physics formula. Understanding the dynamics of the collision is crucial for accurate force estimation.
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Homework Statement


A model of an 80 kg man and one of a 25 kg child in a 1000 kg car and secured with seatbelts. The car was moving at 75kph as it crashed into a break wall.If the collision took 0.2s, calculate the average force exerted on each model by its seat belt

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Homework Equations


f=ma


The Attempt at a Solution


im really confused, I am thinking that for the man: 80x20.8 (75000/3600), the divide by 0.2, so the force is 8333.3 Newtons?

Does the car's weight have anything to do with this?
 
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Hi Dan, welcome to PF!

:biggrin:
dan1995420 said:
im really confused, I am thinking that for the man: 80x20.8 (75000/3600), the divide by 0.2, so the force is 8333.3 Newtons?
Yes
Does the car's weight have anything to do with this?
No.
 
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