What is the average force on the wall?

AI Thread Summary
To find the average force exerted on the wall by the ball, the initial velocity is 10 m/s and the final velocity after rebounding is also 10 m/s. The change in velocity is calculated as 10 m/s (final) - (-10 m/s) (initial, considering direction) = 20 m/s. Using the formula for acceleration, a = (v - v0) / t, results in an acceleration of 100 m/s². Applying F = m*a gives an average force of 50 N, correcting the earlier miscalculation. The average force on the wall is therefore 50 N.
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Homework Statement


A ball hits the wall in a normal direction with v=10m/s. After the hit which lasted 0.2 Seconds, it turned in the same direction with v=10m/S. Knowing that its mass is 0.5 kg, find the average force that hit the wall.

Homework Equations


F=m*a, a= (v-v0)/t

The Attempt at a Solution


a=(0-10)/0.2=-50m/S2, F= 50*0.5= 25N, but the answer is 50N
 
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