What is the average velocity for a bicycle's trip?

AI Thread Summary
To calculate the average velocity of a bicycle trip involving three segments, first resolve the distances into their x and y components. The trip consists of 3.2 km east, 4.7 km at 15° east of north, and another 3.2 km east. The total displacement is found by summing the components of each segment, while the total time is the sum of the individual travel times. The average velocity is then determined by dividing the magnitude of the total displacement by the total time, yielding the result in km/h.
tag16
Messages
95
Reaction score
0

Homework Statement


A bicycle travels 3.2 km due east in 0.10 h, then 4.7 km at 15.0° east of north in 0.14 h, and finally another 3.2 km due east in 0.10 h to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
I need to find the magnitude and direction in degrees


Homework Equations



average velocity= rf-ri/t1-t2 but there is 3 different times and distances not two...

The Attempt at a Solution



I tried to do vector addition A+B and B+C then add them together but that didn't work to well.
 
Physics news on Phys.org
tag16 said:

Homework Statement


A bicycle travels 3.2 km due east in 0.10 h, then 4.7 km at 15.0° east of north in 0.14 h, and finally another 3.2 km due east in 0.10 h to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
I need to find the magnitude and direction in degrees

Homework Equations



average velocity= rf-ri/t1-t2 but there is 3 different times and distances not two...

The Attempt at a Solution



I tried to do vector addition A+B and B+C then add them together but that didn't work to well.

You need to resolve the vectors into their x,y components, then determine the total displacement. That will yield your direction.

For average V = |D|/Total time.

Where |D| is the magnitude of your Displacement determined above, where

D = A + B + C
 
I found the initial velocity for x and y by using the formulas 4.7cos(15.0)= 4.539
4.7sin(15.0)= 1.216
delta t=0.10+0.14
Then I found the x and y components by doing: delta rx= vix(delta t)+0= 1.089
delta ry= viy (delta t)-1/2g(delta t)^2=-1.136
Then I added A+B+C for x and y: x=3.2+1.089+3.2=7.48
y=0+.0096+0
Then added them and took the square root. Then divided that number by the total time. Didn't workout to well...
 
Ok. Try this way.

A = 3.2 i + 0 j

B = 4.7*Sin15 i + 4.7*Cos15 j

C = 3.2 i + 0 j

Then add them together

D = (6.4 + 4.7*sin15) i + 4.7cos 15 j

Your Δt is (.1 + .14 + .1)

Your answer will be in km/h
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top