What is the Average Velocity of a Ship and the Velocity of the River Current?

AI Thread Summary
The discussion focuses on calculating the average velocity of a ship traveling between two points A and B, with speeds of 10 km/h and 16 km/h in opposite directions. The average velocity is incorrectly calculated using the formula for uniformly accelerated motion, leading to confusion about the correct method. The correct average speed is determined by considering total distance and time, resulting in an average speed of 12.3 km/h for the boat and a current velocity of 3 km/h. Participants clarify the distinction between average velocity and average speed, emphasizing the importance of proper definitions in physics calculations. The conversation concludes with a resolution of the misunderstanding regarding the average velocity calculation.
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Homework Statement


A ship goes from A to B at v_1=10 km/h and from B to A at v_2=16 km/h Find: (1) the average velocity of the ship, and (2) the velocity of the river current.


Homework Equations


v_{avg}=(v_1+v_2)/2
v_{AC}=v_{AB}+v_{BC}

The Attempt at a Solution


v_{Boat}-v_{Current}=10km/h
v_{Boat}+v_{Current}=16km/h
v_{Boat}=13km/h, v_{Current}=3km/h
The actual answer for v_{Boat}=12.3km/h Why is that?
 
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What's the definition of average velocity (really average speed)?
 
Change in position/Change in time?
 
kerol9904 said:
Change in position/Change in time?
Try total distance / time.

kerol9904 said:
v_{avg}=(v_1+v_2)/2
This only applies to uniformly accelerated motion, which is not what's going on here.
 
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Ahh... I didn't realize that the equation is only for uniformly accelerated motion. I've got the answer now. Thanks!
 
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