What is the ball's maximum height?

AI Thread Summary
The discussion focuses on calculating the maximum height of a ball thrown upward with an initial vertical speed of 10.8 m/s and an acceleration due to gravity of 9.8 m/s², while neglecting air resistance. Participants clarify the use of kinematic equations, particularly vf² = vi² + 2ad, where vf is the final velocity (0 at maximum height), vi is the initial velocity, a is the acceleration (negative due to gravity), and d is the height. The correct approach involves rearranging the equation to solve for height, leading to the conclusion that the maximum height can be calculated by substituting the known values. The conversation emphasizes understanding the signs of the variables and the proper application of the equations. Overall, the maximum height can be determined through careful application of kinematic principles.
Casey314stl
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Homework Statement


A ball is thrown upward.
What is its maximum height? Its initial
vertical speed is 10.8 m/s and the acceleration
of gravity is 9.8 m/s^2
Neglect air resistance.

Answer in units of m

Homework Equations



dfinal=dintial+vfinalΔt+ 1/2averageaccelerationΔt^2 or v^2final=v^2initial +2averageaccelerationΔd

The Attempt at a Solution


14.2463
 
Last edited:
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No remember that since the object is traveling up it will have a negative speed therefore:

Vf^2=u^2+2is
 
mtayab1994 said:
No remember that since the object is traveling up it will have a negative speed therefore:

Vf^2=u^2+2is
what does u and is stand for?
 
u and v are vectors v is the final speed which in your case will be 0 because the kinetic energy will be 0 at the maximum height so you will be left with 0=speed of the ball -2(speed of gravity)s.
 
so how do i use this to find the height?
 
0=(initial speed)^2-2(speed of gravity)s then once you have this down just solve the equation.
 
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mtayab1994 said:
0=(initial speed)^2-2(speed of gravity)s than once you have this down just solve the equation.
I am solving for Vf^2 which is vertical speed final?
so I plug in 0-2(10.8)=-21.6?
 
Casey314stl said:

Homework Statement


A ball is thrown upward.
What is its maximum height? Its initial
vertical speed is 10.8 m/s and the acceleration
of gravity is 9.8 m/s^2
Neglect air resistance.

Answer in units of m


Homework Equations



dfinal=dintial+vfinalΔt+ 1/2averageaccelerationΔt^2 or v^2final=v^2initial +2averageaccelerationΔd

The Attempt at a Solution


14.2463
Your second equation looks promising. In more compact terms:

vf2 = vi2 + 2*a*d

where vi is the initial velocity, vf the final velocity, a is the acceleration and d is the distance. The distance d is what you're looking for. What values will you assign to the other variables?
 
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