What Is the Bath Temperature When Gold Wire Resistance Increases?

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SUMMARY

The resistance of a gold wire increases from 79 ohms at 30°C to 165 ohms in a liquid bath, indicating a significant temperature change. Using the formula for resistance, R = R(initial)[1 + α(T(final) - T(initial))], where α is the temperature coefficient (0.0034/°C), the calculated final temperature (T_final) is 350.1787°C. This calculation aligns with the provided inputs, confirming the accuracy of the method used. The homework service is not in error; the solution is valid based on the parameters given.

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Homework Statement



At 30±C, the resistance of a segment of gold wire is 79 ohms*.
When the wire is placed in a liquid bath,
the resistance increases to 165 *ohms.
The temperature coefficient is 0.0034/C at 20 degrees celsius.
What is the temperature of the bath? An-
swer in units of C.

Homework Equations



Resistance = R(initial)[1+ alpha (T(final) - T(initial)]

The Attempt at a Solution



165 = 79 * ( 1 + .0034 * (T_final - 30) )

T_final = 350.1787


I'm submitting this and it's saying I'm wrong. Is the homework service in error?
 
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The relevant equation is correct.

The answer is correct for the given inputs.
 

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