What is the correct angle between two vectors?

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The discussion revolves around calculating the angle between two vectors using both the dot product and cross product methods. The user applied a Matlab script to find the angle, obtaining a result of approximately 0.61548 radians. There is confusion regarding a negative sign in part d of the problem, which the user believes is incorrect. Participants agree that the solution manual appears to contain errors, particularly in the calculation of the angle. The consensus is that the manual's solution does not align with the results obtained through the user's calculations.
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Homework Statement


From Analytical Mechanics by Grant R. Fowles & George L. Cassiday.
6rSwBZ0.png

Only problem I am having is with part d.

Homework Equations


##A\cdot B = A_xB_x+A_yB_y+A_zB_z##
##sin(\theta) = \frac{|A\times B|}{AB}##

The Attempt at a Solution


y2IqTYi.png

I did it by hand but also ran the following Matlab script:
Matlab:
A = [1,1,1];
B = [1,1,0];
theta = acos(dot(A,B)/norm(A)/norm(B))
theta = asin(norm(cross(A,B))/norm(A)/norm(B))
Both formulas return 0.61548. I think the minus sign in part d should not be there, but I might be missing something. A second pair of eyes would be appreciated.
 
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Where do you get the 1-1 in the numerator from?

(1*1)+(1*1)+(1*0)=1+1.

You can also use the result of (c) to get the angle.
(c) doesn't look like a final answer by the way.
 
mfb said:
Where do you get the 1-1 in the numerator from?

(1*1)+(1*1)+(1*0)=1+1.

You can also use the result of (c) to get the angle.
(c) doesn't look like a final answer by the way.
The image is the solution from the manual. I used the Matlab code and got and angle of .6 in radians. It appears the solution manual was incorrect.
 
Yes, the solution shown in the second image is wrong.
 
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