What is the correct answer for the electric charge question?

AI Thread Summary
The discussion centers around confusion regarding the correct answers to electric charge problems involving conducting spheres and forces. Participants express differing opinions on the outcomes of charge distribution when spheres touch, with some believing the answer should be A while others argue for C. Key points include the importance of understanding charge distribution in identical versus non-identical spheres and the need for clarity in problem-solving methods. Additionally, there is a focus on the distinction between solid spheres and hollow shells in the context of electric fields. Ultimately, the conversation highlights the complexities of electric charge interactions and the necessity for precise calculations.
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Electric charge question[Updating...]

1)
testbank-28-chap21_zps8fb3ad78.png

I tried to do this homework, but my answer is all , of course it is not as same as this question's answer. That is my procedure:
+) First, 2 charged have a same chagre Q, after these also have a same charge q=(Q-Q').
+) F'/F=[(Q-Q')/Q]^2.
+) I substituting all answer, and it is correct all, i can have 1 Q'.
Why the answer is C.

2)
testbank-28-chap21_zps9b70a217.png

F=Q.q/4piE(a^2+d^2)
F max when a^2+d^2 min=> d^2 min when d=0 why the answer is E, i think a true answer is A

3)
testbank-44-chap21_zps5e707e6d.png

Following my textbook:
testbank-44-chap21_zps07104445.png

it is also existing an electric field inside a insulator. So the answer E is not correct, because it still have Electric force. I think A is true. Am I right?
 
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cuongbui1702 said:
1)
I tried to do this homework, but my answer is all , of course it is not as same as this question's answer. That is my procedure:
+) First, 2 charged have a same chagre Q, after these also have a same charge q=(Q-Q').
+) F'/F=[(Q-Q')/Q]^2.
+) I substituting all answer, and it is correct all, i can have 1 Q'.
Why the answer is C.
Let Q be the initial charge on A and B. (Express the initial force F in terms of Q.) When C touches A, what are the resulting charges on A and C? Then when C touches B, what are the resulting charges on C and B? Once you have the final charges on A and B expressed in terms of Q, then find an expression for the new force between A and B.
 
To get a resulting charges on A and C or B and C i think it is quite hard, or i don't know to calculate it
 
cuongbui1702 said:
To get a resulting charges on A and C or B and C i think it is quite hard, or i don't know to calculate it
No, it's easy. And unless you know how it works, you cannot solve the problem.

Here's how it works: When two identical conducting spheres are touched, the total charge distributes uniformly between the two of them.
 
Oh thank you, that is amazing thing i have learned today, i got the answer, it is as same as with this( sorry about my terrible English). Why i can't see this in my textbook University Physics with Modern Physics, 13th Edition of Young and Freeman
 
Who can help me Question2 and 3, please
 
cuongbui1702 said:
2)
F=Q.q/4piE(a^2+d^2)
F max when a^2+d^2 min=> d^2 min when d=0 why the answer is E, i think a true answer is A
You need an expression for x-component of the force, not the total force.

(Don't keep adding problems to the original post. That makes things confusing to follow and respond to. Best to solve one problem before starting another; usually best to have one problem per thread, unless they are very related.)
 
cuongbui1702 said:
3)
Following my textbook:

it is also existing an electric field inside a insulator. So the answer E is not correct, because it still have Electric force. I think A is true. Am I right?
No, you are not right. The illustration from the book describes a uniformly charged sphere, but the problem is about a spherical shell (a balloon).
 
Doc Al said:
You need an expression for x-component of the force, not the total force.

(Don't keep adding problems to the original post. That makes things confusing to follow and respond to. Best to solve one problem before starting another; usually best to have one problem per thread, unless they are very related.)
- Oh, I read wrong problem :(. But, when i did it again, my process is long(i use derivatives), maybe in this question, i substituting all answers is faster than my process.
- I am scared, admin delete my post when i make a lot of question :(
 
  • #10
Doc Al said:
No, you are not right. The illustration from the book describes a uniformly charged sphere, but the problem is about a spherical shell (a balloon).

What is the difference between them??
 
  • #11
cuongbui1702 said:
What is the difference between them??
A balloon is hollow shell with nothing inside. The text from your book describes a solid sphere of charge, not just a shell.
 
  • #12
cuongbui1702 said:
- Oh, I read wrong problem :(. But, when i did it again, my process is long(i use derivatives), maybe in this question, i substituting all answers is faster than my process.
I suggest you actually work it out with derivatives; it's not that bad and it simplifies quickly.
 
  • #13
Doc Al said:
A balloon is hollow shell with nothing inside. The text from your book describes a solid sphere of charge, not just a shell.
Because English is my second language, so that it is hard for me to recognize what it is, if i don't have pictures :D
 
  • #14
Doc Al said:
No, it's easy. And unless you know how it works, you cannot solve the problem.

Here's how it works: When two identical conducting spheres are touched, the total charge distributes uniformly between the two of them.

Doc AI, i have a same problem but my answer is not as same as question's answer. Following you, it must be A.
testbank-27-chap23_zps1c18ff99.png
 
  • #15
cuongbui1702 said:
Doc AI, i have a same problem but my answer is not as same as question's answer. Following you, it must be A.
In this example, the conducting spheres are not identical. (The more general principle is that the potential will be the same after they touch.)
 
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