What is the correct concentration of Cl- in various aqueous solutions?

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Discussion Overview

The discussion revolves around determining the correct concentration of Cl– in various aqueous solutions, specifically focusing on the molarity and molality of solutions containing HgCl2 and NH4Cl at 25°C. Participants explore the implications of solubility and the definitions of concentration in this context.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states that the correct answer is D, which provides a 2 m Cl– concentration using NH4Cl in 22.5 mol of H2O, while choices A and B are eliminated due to the poor solubility of HgCl2.
  • Another participant questions the definition of molar concentration and suggests calculating concentrations for options C and D.
  • A participant expresses confusion regarding the role of temperature in calculating concentrations but later clarifies their understanding of how to derive molarity from moles and liters.
  • There is a query about whether the concentration being discussed is molar or molal.
  • One participant acknowledges that rounding may affect the exact concentration values, suggesting that neither calculated concentration is precisely 2.

Areas of Agreement / Disagreement

Participants express differing views on the definitions and calculations of molar versus molal concentrations, and there is no consensus on the exact values due to rounding and solubility considerations.

Contextual Notes

Participants note that the solubility of HgCl2 affects the calculations, and there are unresolved aspects regarding the definitions of molarity and molality, as well as the impact of temperature on these calculations.

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Homework Statement



Which of the following aqueous solutions has a Cl– concentration of 2 m at 25°C?
A.

271 g of HgCl2 in 55 mol of H2O
B.

271 g of HgCl2 in 22.5 mol of H2O
C.

53 g of NH4Cl in 55 mol of H2O
D.

53 g of NH4Cl in 22.5 mol of H2O.

Correct Answer
Explanation:
D. Pure water has a concentration of 55 M and density of 1 kg/L. 55 moles of water represent 1 L (1 kg) and 22.5 moles of water represent 0.5 L (0.5 kg). HgCl2 demonstrates poor water solubility and will dissociate little. Therefore, 1 mol of HgCl2 placed in either water 1 kg or 0.5 kg of water will not achieve a 2 m Cl– solution, eliminating choices A and B. NH4Cl is water soluble and has a molecular weight of 53 g/mol. Choice C is a 1 m NH4Cl (1 m Cl–) solution and Choice D is a 2 m NH4Cl (2 m Cl–) solution.


Homework Equations



No equation. Conceptual

The Attempt at a Solution



I understand that we are looking for the answer that has a concentration of 2 M for chlorine and I understand that A and B are wrong because that compound is insoluble in water but what I don't understand is why we get a 2 molar solution when we add it to half a liter of water vs getting a 1 molar solution when we add it to 1 liter of water
 
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What is the definition of molar concentration?

Have you tried to calculate concentrations for C and D?
 
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Oh yes I understand now. I got confused because I thought we had to factor in temperature somehow. But yes I see how you get a two molar concentration and a 1 molar concentration when you solve for moles and liters and solve for molarity. Thanks.
 
Is that molar or molal?
 
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Good point.

Not that it changes much, as the values used are rounded down, so the exact concentration that can be calculated is not exactly 2 in neither (l/r) case, just close to 2.
 
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