What is the Correct Formula for Calculating Vapour Pressure of Solutions?

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Discussion Overview

The discussion revolves around the correct formula for calculating the vapor pressure of solutions, specifically in the context of Raoult's Law and the influence of solute concentration on vapor pressure. Participants explore theoretical aspects and practical implications of the formula.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant proposes the formula ##P= \chi_{solvent}P^o _{solvent}##, suggesting that it should yield a specific vapor pressure result based on given values.
  • Another participant questions the validity of the formula, arguing that it implies pressure independence from the solute fraction.
  • A different participant introduces the concept of adding pressure components from multiple volatile solutions to find total vapor pressure, referencing Raoult's Law.
  • One participant asserts that vapor pressure does depend on the fraction of the solute, citing real-life examples of colligative properties, such as the boiling point elevation of saltwater.
  • Another participant critiques the relevance of colligative properties to the original problem, suggesting that it confuses the discussion.
  • A later reply acknowledges a misunderstanding regarding the volatility of methanol, indicating that it should be considered in the calculations.

Areas of Agreement / Disagreement

Participants express disagreement regarding the application of the vapor pressure formula and the relevance of colligative properties. There is no consensus on the correct approach or interpretation of the problem.

Contextual Notes

Participants highlight potential misunderstandings regarding the volatility of certain solutes and the assumptions underlying the application of Raoult's Law. The discussion reflects varying interpretations of the formula and its implications.

DottZakapa
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Homework Statement
Calculate the vapour pressure at 21.0°C of an ideal solution of water and methanol (CH3OH, P°=100 mmHg at 21.0°C) that contains 9.0 mol of water and 0,50 mol of methanol. Vapour pressure of water at 21.0°C is 18.7mmHg.
Relevant Equations
Solutions
Isn't the formula to be applied ##P= \chi_{solvent}P^o _{solvent}##?
in which ##P^o _{solvent}##= 18.7mmHg and

##\chi_{solvent}= \frac{mol_{solvent}}{mol_{solvent}+mol_{solute}}=\frac{9.0 mol}{9.0 mol+0,50 mol}##

but seems doesn't leads to the expected result
 
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Hi,

DottZakapa said:
Isn't the formula to be applied ##P= \chi_{solvent}P^o _{solvent}##?
Very unlikely: the pressure would be independent on the fraction solute ?

##\ ##
 
BvU said:
Hi,

Very unlikely: the pressure would be independent on the fraction solute ?

##\ ##

On the contrary, vapor pressure does depend on the fraction of the solute. Vapor pressure lowering is one of the four colligative properties that one has real-life experience with. For example, salt water boils at a higher temperature than pure water because salt water's vapor pressure equals 1 ATM at a higher temperature. :)

Link: https://www.chem.fsu.edu/chemlab/chm1046course/colligative.html
 
docnet said:
On the contrary, vapor pressure does depend on the fraction of the solute

You are:
1. missing the point of BvU's post
2. posting unrelated info (problem has nothing to do with colligative properties)
3. confusing OP (your post on Raoult's law was pointing in the right direction, now you are derailing)

None of that is helpful.
 
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ok, i was neglecting the methanol, basically i was considering it as non volatile solute, in that case I should not consider it, but here it must be taken into account. thanks
 
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