Chemistry What is the Correct Formula for Calculating Vapour Pressure of Solutions?

AI Thread Summary
The correct formula for calculating vapor pressure of solutions is P = χ_solvent * P^o_solvent, where P^o_solvent is the vapor pressure of the pure solvent. The mole fraction of the solvent, χ_solvent, is calculated using the moles of solvent and solute. It is clarified that vapor pressure does depend on the fraction of solute, contrary to some initial confusion. The discussion highlights the importance of considering all components, including volatile solutes, when applying Raoult's Law. Overall, accurate calculations require careful consideration of all variables involved in the solution.
DottZakapa
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Homework Statement
Calculate the vapour pressure at 21.0°C of an ideal solution of water and methanol (CH3OH, P°=100 mmHg at 21.0°C) that contains 9.0 mol of water and 0,50 mol of methanol. Vapour pressure of water at 21.0°C is 18.7mmHg.
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Isn't the formula to be applied ##P= \chi_{solvent}P^o _{solvent}##?
in which ##P^o _{solvent}##= 18.7mmHg and

##\chi_{solvent}= \frac{mol_{solvent}}{mol_{solvent}+mol_{solute}}=\frac{9.0 mol}{9.0 mol+0,50 mol}##

but seems doesn't leads to the expected result
 
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Hi,

DottZakapa said:
Isn't the formula to be applied ##P= \chi_{solvent}P^o _{solvent}##?
Very unlikely: the pressure would be independent on the fraction solute ?

##\ ##
 
You seem to be on the right track. I think this will help:

"When two or more volatile solutions are mixed, each pressure component of the mixed solution is added together to find the total vapor pressure.
PTotal = Psolution A + Psolution B + ..."

source: https://www.thoughtco.com/raoults-law-with-volatile-solutions-609525
 
BvU said:
Hi,

Very unlikely: the pressure would be independent on the fraction solute ?

##\ ##

On the contrary, vapor pressure does depend on the fraction of the solute. Vapor pressure lowering is one of the four colligative properties that one has real-life experience with. For example, salt water boils at a higher temperature than pure water because salt water's vapor pressure equals 1 ATM at a higher temperature. :)

Link: https://www.chem.fsu.edu/chemlab/chm1046course/colligative.html
 
docnet said:
On the contrary, vapor pressure does depend on the fraction of the solute

You are:
1. missing the point of BvU's post
2. posting unrelated info (problem has nothing to do with colligative properties)
3. confusing OP (your post on Raoult's law was pointing in the right direction, now you are derailing)

None of that is helpful.
 
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ok, i was neglecting the methanol, basically i was considering it as non volatile solute, in that case I should not consider it, but here it must be taken into account. thanks
 
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