What is the Criterion for Total Internal Reflection?

  • Thread starter Thread starter Larrytsai
  • Start date Start date
  • Tags Tags
    Optics
AI Thread Summary
Total internal reflection occurs when light moves from a denser medium to a less dense medium and the angle of incidence exceeds the critical angle. The critical angle can be calculated using the formula θ_critical = sin^(-1)(n1/n2), where n1 is the refractive index of the less dense medium and n2 is that of the denser medium. In the case of a light ray entering air from diamond, with n for diamond at 2.5 and air at 1.00, the critical angle can be determined, and if the angle of incidence is greater, total internal reflection will occur. Snell's law fails when the sine of the refracted angle exceeds one, indicating no refraction and the presence of total internal reflection. Understanding these principles is crucial for solving related optical problems.
Larrytsai
Messages
222
Reaction score
0
Hey, on my test today on the bonus question was asking : if a light ray shines at 50 degrees into a diamond then enters air at what angle? n for diamond = 2.5
n for air = 1.00.

I know the answer is total internal reflection cause i guessed it and got it right, but how do you prove it and how do u knw if it is total internal reflection?
 
Physics news on Phys.org
also if you use the formula ni sin theta i= nr sin theta r you end up not being able to complete the formula
 
Well, what is the criterion for Total Internal Reflection? You should know this. It occurs when a light ray is moving from a more optically dense medium (n2 below) into a less optically dense medium (smaller index of refraction n1 below), and the angle of incidence is so large, that Snell's law breaks down...it produces a sine for the refracted angle that is greater than one. In fact, the critical angle occurs when the sine is equal to one. In other words:

n_2 \sin \theta_2 = n_1 \sin \theta_1

\frac{n_2}{n_1} \sin \theta_2 = \sin \theta_1 = 1

\sin \theta_2 = \frac{n_1}{n_2}

\theta_2 = \theta_{\textrm{critical}} = \sin^{-1}\left(\frac{n_1}{n_2}\right)

This is the critical angle...for angles larger than this, the angle of the refracted ray is undefined...and there is no refracted ray. Instead, total internal reflection occurs.
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top