What is the Definition of Infinite Series and Its Notation?

gotjrgkr
Messages
84
Reaction score
0
infinite series!

Homework Statement


Hi!
I've learned that the definition of a sequence of elements of complex numbers is as follows;
a sequence is a function whose domain is a set of all positive integers with values in a set consisting of all complex numbers. (Denote the set of all complex numbers by C from now on)
Now, let {a_{n}} be a sequence of elements of C.
Then, as you know, infinite series is defined as a sequence of partial sums b_{k} = \sum^{k}_{n=1}a_{n}.If the limit of the sequence exists, then it is said that the infinite series{b_{k}} is convergent. In this case,
a value of the limit of the sequence is called a sum of the series and is denoted by
lim_{k\rightarrow}\inftyb_{k}.

Now, here is my question.
I've seen a notation like this; \sum_{n=p}^{\infty}a_{n} where p is any integer. If p is not 1, then I have no idea how to interpret this expression...
What is the exact definition of a kind of a sum above..?


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org


It's a_p+a_{p+1}+a_{p+2}+... It's the difference between the sum of the whole series and the (p-1)th partial sum.
 


Dick said:
It's a_p+a_{p+1}+a_{p+2}+... It's the difference between the sum of the whole series and the (p-1)th partial sum.

Then what can you say about ,for example,\sum^{\infty}_{n=-3}a_{n}??
Do you think that it is a difference between the sum of a sequence a_{1},a_{2},... and (a_{-3}+...+a_{0})?

I want to know a kind of a definition such as a form of limit expression...as I showed in the case of \sum^{\infty}_{n=1}a_{n}.
 


gotjrgkr said:
Then what can you say about ,for example,\sum^{\infty}_{n=-3}a_{n}??
Do you think that it is a difference between the sum of a sequence a_{1},a_{2},... and (a_{-3}+...+a_{0})?

I want to know a kind of a definition such as a form of limit expression...as I showed in the case of \sum^{\infty}_{n=1}a_{n}.

You can write a series starting at any value of n, like p in the example you give. If you take a_n=1/(2^n), then the sum from n=1 to infinity is 1. The sum from n=0 to infinity is 2. The sum from n=3 to infinity is 1/4. They only differ from the sum from n=1 to infinity by a finite number of terms, as you said. If a series converges then the series starting a different limits will also converge. Just to a slightly different limit. There's no law that says the first term of a series must be a_1.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top