What is the density and uncertainty of a given object?

AI Thread Summary
The density of the object is calculated to be approximately 9223.9 kg/m^3 using the formula p=6M/piD^3. The uncertainty in density is found to be 1901 kg/m^3, which raises concerns about its magnitude. However, the relative uncertainty of the density is about 0.2, which is considered acceptable compared to the relative uncertainty of the diameter at 0.067. The calculations confirm that the results are correct despite the large uncertainty value. Overall, the discussion emphasizes the importance of understanding density and uncertainty in measurements.
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Homework Statement


Calculate the density and its ucertainty...

Mass = 0.0163 kg
Uncertainty Mass = 0.0001 kg
Diameter = 0.015m
Uncertainty Diameter = 0.001m


Homework Equations


p=6M/piD^3
^p/p=^m/m + 3^D/D

The Attempt at a Solution


p= 6 x (0.0163)/ pi(0.015^3)
= 9223.9 kg/m^3

^p/9223.9= 0.0001/0.0163 + 0.003/0.015
^p= 1901 kg/m^3

The value for ^p just seems too large?
 
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Your result is correct. The relative uncertainty of the density is about 0.2, which is not too big compared to the 0.067 relative uncertainty of the diameter.

ehild
 

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