What is the Density of a 6.8-kg Piece of Metal That Displaces 1 Liter of Water?

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To calculate the density of a 6.8-kg piece of metal that displaces 1 liter of water, one must use the formula for density, which is mass divided by volume. The volume of the displaced water is 1 liter, equivalent to 0.001 cubic meters. Therefore, the density can be calculated as 6.8 kg divided by 0.001 m³, resulting in a density of 6800 kg/m³. It's important to note that mass is measured in kilograms, while weight is a different concept. Understanding this distinction is crucial for accurate calculations.
sharonita
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Heres the question:
A 6.8-kg piece of metal displaces 1 liter of water when submerged. Calculate its density.

So I have no idea where to begin or how the displacement relates to the density. What can you suggest? Thanks!
 
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i reallllyy need help =\
anybody?
 
Density equals mass divided by volume. If the object displaces 1 liter of water, then it has a volume of 1 liter. You also have to know that 1 liter = 0.001 cubic meters. The objects density is 6.8kg/0.001m^3 or 6800kg/m^3.
 
But wasnt the weight 6.8kg?
 
Yes the mass is 6.8kg and the volume is 1liter which is equal to 0.001m^3. The density is mass divided by volume which is 6.8kg/0.001m^3. Do 6.8 divided by 0.001 on a calculator; what answer do you get?
 
sharonita said:
But wasnt the weight 6.8kg?


Nope, the mass was 6.8 kg. The kilogram is a unit of mass, not weight.
 
6800...thanks!
 
ohhhh. okay thanks a bunch!
im such a newbie, that's all. :)
 
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