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Homework Statement
A cylindrical container with a cross sectional area of 65.2 cm^{2} holds a fluid of density 806kg/m^{3}. At the bottom of the container the pressure is 116 kPa
a) What is the depth of the fluid?
b) Find the pressure at the bottom of the container after an additional 2.05 \times 10^{-3} m^{3} of this fluid is added to the container. Assume no fluid spills out of the container.
Homework Equations
The Attempt at a Solution
a) A = 65.2 cm^{2}
\rho = 806 kg/m^{3}
P(bottom) = 116 kPa = 1.16 \times 10^{5} Pa
closed manometer \rightarrow P = \rhogh
h = \frac{P}{\rhog} = \frac{1.16 \times 10^{5}}{806 \times 9.81}
= 14.67 m