What is the Differentiation Problem for the Function g(t)=t√(4-t)?

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g(t)=t\sqrt{4-t},t<3
g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2
 
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I can not figure out how to use this text stuff, forget I said anything at all.
 
JoshHolloway said:
g(t)=t\sqrt{4-t},t<3
g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2

You got it Josh. Here's it is in LaTex. Just click on it to see the code:

g^{'}(t)=\frac{-t}{2\sqrt{4-t}}+\sqrt{4-t}
 

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