What Is the Direction of the Magnetic Force on a Proton?

AI Thread Summary
The discussion revolves around calculating the magnetic force on a proton moving in a magnetic field. The proton's mass is given as 1.67 x 10^-27 kg, with a velocity of 2.9 x 10^6 m/s in a 6.8 T magnetic field. The force was calculated to be 3.2E-12 N, but the participant struggles with determining the direction of the force. They are advised to use Fleming's Left Hand Rule to find the correct direction of the magnetic force. The conversation highlights the importance of understanding both the magnitude and direction of forces in magnetic fields.
eric.c
Messages
3
Reaction score
0
QUESTION 1

Homework Statement



Determine the magnetic force acting on an proton (m = 1.67 x 10-27 kg) moving at 2.9 x 106 m/s in a magnetic field of 6.8 T. The proton is moving south. The magnetic field points straight down.

Homework Equations



F = qvBsinø

The Attempt at a Solution



I assumed that down means into the earth, and south means bearing to the south pole, so ø is 90°. I solved the equation and F = 3.2E-12N

However, I can't seem to figure out the direction of the force.


QUESTION 2

Homework Statement



Determine the direction of force that the proton experiences in traveling through the field. Remember that the X represents that the magnetic field points into the page.

R90OJ.png


Homework Equations



none that I can think of

The Attempt at a Solution



I don't even know where to start. :(
 
Physics news on Phys.org
You can use Fleming's Left Hand Rule to figure it out
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top