What is the Efficiency of a Carnot Refrigerator?

Click For Summary

Discussion Overview

The discussion centers on the efficiency of a Carnot refrigerator, exploring the relationship between the Carnot cycle and the calculation of efficiency for refrigeration systems. Participants examine whether the same formula for efficiency used in Carnot engines can be applied to refrigerators, and the implications of viewing the cycle in reverse.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions if the efficiency of a Carnot refrigerator can be calculated using the same formula as for a Carnot engine: η = 1 - \frac{T_{cold}}{T_{hot}}.
  • Another participant asserts that since the cycle is viewed in the opposite direction, the efficiency should be considered the inverse.
  • A participant deduces an alternative expression for efficiency: η = \frac{T_h}{T_h-T_c}, and raises concerns about the implications of this expression yielding values greater than one when T_c is slightly below T_h.
  • Discussion includes the clarification that heat pumps and air conditioners do not perform mechanical work but instead move heat, leading to outputs that exceed the input power.
  • One participant emphasizes that when discussing heat engines in reverse, the term "efficiency" is replaced by "COP" (coefficient of performance), which can exceed one, unlike efficiency.
  • Another participant provides a practical example of an air conditioner functioning as a heat pump, illustrating the relationship between heat moved and electrical energy consumed, and how this relates to COP.

Areas of Agreement / Disagreement

Participants express differing views on the application of efficiency formulas to Carnot refrigerators, with no consensus reached on whether the same efficiency formula applies or how to interpret the results derived from different expressions.

Contextual Notes

Participants note that the definitions and assumptions surrounding efficiency and COP may lead to confusion, particularly regarding the implications of values greater than one in the context of refrigeration systems.

KFC
Messages
477
Reaction score
4
In the textbook, it reads: the reverse of carnot cycle is just a refrigerator or heat pump. In this sense, except for the direction of carnot cycle is reverse, could I say the way to calculate the efficiency of the carnot refrigerator is the same? That is, could be still use

\eta = 1 - \frac{T_{cold}}{T_{hot}}

to calculate the efficiency of Carnot refrigerator?

Thanks
 
Science news on Phys.org
No: since the cycle is being viewed from the opposite direction (basically), the efficiency is the inverse.
 
russ_watters said:
No: since the cycle is being viewed from the opposite direction (basically), the efficiency is the inverse.

You are right. I deduce the efficiency for the Carnot refrigerator similar to the steps for deducing the efficiency for Carnot engine. I've got something like this

[size=+2]
<br /> \eta = \frac{T_h}{T_h-T_c}<br />
[/size]

But with this expression, if T_c is just a bit below T_h but still be positive, the efficiency will be large than one? How's that possible? How to explanation this? What's the physical significance of this result?
 
Well, since these devices don't do mechanical work, the output is moved heat. In fact, for both heat pumps and air conditioners, the amount of heat moved is greater than the input power.
 
re Russ Watters:
An air conditioner IS a heat pump -- just turn it around in the window!
iiuc, modern combination A/Cs-heat pumps (Mitsubishi's/Fujitsu's, etc) don't mechanically switch air flows, they re-route the refrigerant through different coils, or some such thing.

To the OP, when you run a heat engine in reverse (ie, A/Cs, heat pumps), you no longer speak of efficiency, but of COP -- coefficient of performance, or whatever else engineers like to call it. And as you observed, it is always greater than 1, just as efficiency is always less than 1.

There is no violation of thermo here, just a statement that if heat can drive a motor, a motor can pump heat. This pumped heat, plus the inevitable decay of the motor's work into heat, gives the appearance of more than you put in, but it really is not.
 
Last edited:
HoloBarre said:
re Russ Watters:
An air conditioner IS a heat pump -- just turn it around in the window!
iiuc, modern combination A/Cs-heat pumps (Mitsubishi's/Fujitsu's, etc) don't mechanically switch air flows, they re-route the refrigerant through different coils, or some such thing.
Different way of saying the same thing, but yes, you are correct. It might lead to a better explanation, for people confused about the COP concept...

If a window air conditioner moves 1 kW of heat energy from the cold coil (the evaporator coil) to the hot coil (condenser coil) while consuming 0.5kW of electrical energy, it dissipates a total of 1.5 kW at the hot coil. That's an efficiency of .5/1.5=.333. Flip it around in the window and you get 1.5 kW of heating for an electrical input of 0.5 kW, or a COP of 1.5/.5=3.0.
 
Last edited:

Similar threads

  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
14K
Replies
12
Views
3K
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
14K
  • · Replies 5 ·
Replies
5
Views
2K