What is the Efficiency of the system?

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The discussion centers on calculating the efficiency of a hand crank system used to lift a 12.0 kg bucket of water 8.5 m with a force of 40.0 N over a distance of 15.0 m. The actual work done is calculated as 600 J, while the useful work done is determined to be 1000 J. This results in an efficiency calculation of 166%, which raises concerns since efficiency cannot exceed 100%. The discrepancy suggests there may be an error in the problem statement or assumptions made in the calculations. The discussion highlights the importance of verifying inputs and understanding the principles of work and efficiency in mechanical systems.
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Question:

An hand crank is used to life a bucket of water from a well. The bucket and water have a combined mass of 12.0 kg and must be raised 8.5 m. The force used to lift this load is 40.0 N and must be applied over a total circular distance of 15.0 m. What is the efficiency of the system?


Related Equations:
W = (Force) (displacement)
W useful = (mass) (gravity) (height)
% Efficiency = useful work done / actual work done x 100%

Attempt at a Solution:

F = 40.0N
m = 12.0kg
h = 8.5m
g= 9.8N/kg
d= 15.0m
w= ?
w= (F)(d)
w= (40.0N) (15.0m)
w= 600J
w useful = ?
% Efficiency = ?
W useful = m g h
W useful = (12.0kg) (9.8N/kg) (8.5m)
W useful = 999.6J
w useful = 1000J
% Efficiency = useful work done / actual work done x 100%
% Efficiency = 1000J/600J x 100%
% Efficiency = 166%


The reason why I'm not sure I got the correct answer is because the efficiency of the system is over 100% instead of under...
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Looks like something wrong with the problem statement.
 
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