What is the energy dissipated in the wire?

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The discussion revolves around calculating the energy dissipated in a wire connecting two charged metal plates. The maximum current in the wire is determined to be 4.17×10^5 A, and the largest electric field is calculated at 1.80×10^5 V/m. The user is seeking assistance with part c, specifically how to calculate the total energy dissipated in the wire. They suggest that the energy dissipated may be transferred to the capacitor and explore the relationship between force, work, and potential energy. The conversation emphasizes the need to understand the equations relating electric force and energy to solve the problem effectively.
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Homework Statement



Two 10-cm-diameter metal plates are 1.0 cm apart. They are charged to \pm12.5 nC. They are suddenly connected together by a 0.224-mm-diameter copper wire stretched taut from the center of one plate to the center of the other.

a) What is the maximum current in the wire?
b) What is the largest electric field in the wire?
c) What is the total amount of energy dissipated in the wire?

Homework Equations





The Attempt at a Solution


i already got part a an b.. the answers are 4.17×10^5 A and 1.80×10^5 V/m , respectively

part c...i can't figure it out...how to calculate the energy?
help

i think the energy dissipated from the wire goes to the capacitor
 
Physics news on Phys.org
What would be the force exerted by the e-field on a point charge of q? Now how is work and hence potential energy related to this force?
 
what is the charge on the point charge

F = qE
W = Fdcos(angle)

W = qEd
U(electric potential energy ) = - W(electric)
then
U = -qEd
 

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