What is the Equilibrium Temperature When Brass Meets Water?

AI Thread Summary
To find the equilibrium temperature when 50 grams of brass at 200°C is dropped into a 50-gram aluminum cup containing 160 grams of water at 20°C, the principle of conservation of energy is applied. The equation mcΔT=mcΔT is used, where the heat lost by the brass equals the heat gained by the water and aluminum. It's important to account for the specific heats of brass, aluminum, and water in the calculations. The brass will lose heat, resulting in a negative term in the equation. Ultimately, the solution requires setting up the equation correctly and solving for the equilibrium temperature.
Damien20
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Homework Statement


50 grams of brass shot are heated to 200C° and dropped into a 50-g aluminum cup containing 160-g of water. The temperature of the cup and water are 20 C°. what is the equilibrium temperature.



Homework Equations


mcΔT=mcΔT





The Attempt at a Solution


I've made a few different attempts but all of them are horribly wrong and long.

If anyone can drop a hint or a formula to work off that would be awesome.
 
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There are three items that reach thermal equilibrium, brass, aluminum and water. Assuming that no heat is lost to the environment, there should be three terms of the mcΔT type adding up to zero. The brass term will turn out negative because the temperature of the brass will have to drop. You need to look up the specific heats for the three items if you don't already have them.
 
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