What is the Expected Wheel Tax Revenue for the City in November?

AI Thread Summary
The city expects to generate wheel tax revenue from 74,806 registered automobiles, each paying an annual fee of $50. Assuming a uniform distribution of birthdays, the expected revenue for November can be calculated using the formula E(X) = (74,806 * 50) * (30/365), which accounts for the number of days in November. For February, the expected revenue would be E(X) = (74,806 * 50) * (28/365) in a non-leap year. The discussion highlights the importance of considering the distribution of birthdays when estimating tax revenue. This method provides a framework for calculating expected revenues in different months.
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1. A city has 74,806 registered automobiles. Each is required to display a bumper decal showing that the owner paid an annual wheel tax of $50. By law, new decals needed to be purchased during the month of the owner’s birthday. How much wheel tax revenue can the city expect to receive in November?



2. expected value = E(X) = summation(x*f(x))
Leibnitz's rule




3. I thought there was not enough information in the problem. Can we assume that people are equally likely to be born in the different months of the year?
Anyway, all I have is E(X) = (74,506*50)*1/12
where the part in parenthesis is x and 1/12 is the probability function
(not sure).
 
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I think you are right that you need to assume a uniform distribution of birthdays, and I would write that assumption out explicitly.

Just one question about your answer - what is the expected revenue in (say) February?
 
Going by the same approach, it would be the same answer. Did you have something else in mind?
 
I think each day is equally likely...
 
Ah, I see. So for November, E(X) = (74,506*50)*30/365
and for February, assuming it's not a leap year, it would be E(X) = (74,506*50)*28/365

Thanks for the help.
 
That is the right answer for a non-leap year - can you figure it out for an average year?
 
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