What Is the Focal Length of the Lens When the Nickel's Image Doubles in Size?

Thread starter goWlfpack
Start date Nov 14, 2008
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Focal Focal length Length

AI Thread Summary

To determine the focal length of the lens when the nickel's image doubles in size, the magnification formula M = h'/h = - (p/q) is relevant. Given that the image diameter is twice that of the nickel and the lens is positioned 2.90 cm from the nickel, the problem can be approached using the lens formula, which includes the term "1/f." The focal length can be calculated by rearranging the lens equation based on the provided distances and magnification. This problem emphasizes understanding the relationship between object distance, image distance, and focal length in lens optics. The focal length can be determined through these established optical principles.

Nov 14, 2008

goWlfpack

Homework Statement

The nickel's image in the figure below has twice the diameter of the nickel when the lens is 2.90 cm from the nickel. Determine the focal length of the lens.

Homework Equations

M = h'/h = - (p/q)

The Attempt at a Solution

i don't really know how to start this one... eek

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Nov 14, 2008

Redbelly98

Staff Emeritus

Science Advisor

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There is a well-known equation for lenses, try that one.

Hint: it has a "1/f" in it.

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