What Is the Force on the Wheaties Box from the Cheerios Box?

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The discussion centers on calculating the force exerted by a Cheerios box on a Wheaties box when both are subjected to a horizontal force. Given that the frictional force on the Cheerios box is 2N and on the Wheaties box is 4N, the total applied force is 12N. Participants suggest applying Newton's second law to analyze the system as a whole and then individually to each box. There is also a request for clarification on whether the boxes are stacked and for a diagram to aid understanding. The conversation emphasizes the need for a systematic approach to solve the problem effectively.
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A box of cheerios and a box of wheaties are accelerated by a horizontal force F applied to the cheerios box. The magnitude of the frictional force on the cheerios box is 2N, and the magnitude of the frictional force on the wheaties box is 4N. If the Magnitude of F is 12N, what is the magnitude of the force on the wheaties box from the cheerios box

Im not sure if this is right or if this even has anything to do with the problem:

fk(cheerios) = Mu(k)N
2N = Mu(k)[9.8 x 1]
Mu(k)[cheerios] = 0.204N

...
Mu(k)[wheaties] = 0.136N

What do i do to find the answer?
 
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Anyone ?
 
Are the boxes on top of one another? Please draw a diagram and host it on eg. ImageShack.
 
http://img443.imageshack.us/img443/1299/pic004sg.png
 
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Try this:
(1) Apply Newton's 2nd law to both boxes together. Deduce whatever you can.
(2) Using what you learned, now apply Newton's 2nd law to one of the boxes separately.
 
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