What is the Force per Meter on Conductor C in a Three-Phase Transmission Line?

AI Thread Summary
In a three-phase transmission line with conductors A, B, and C arranged in an equilateral triangle, conductors A and B carry 75A while conductor C carries a return current of 150A. The discussion focuses on calculating the force per meter on conductor C due to the magnetic fields generated by conductors A and B. Participants suggest using the magnetic field equations and the force equation F = i∫(B×dl) to determine the forces acting on conductor C. There is confusion regarding how the current in conductor C affects the magnetic field and whether it cancels out the contributions from A and B. The conversation emphasizes the need to clarify the interactions between the currents and the resulting magnetic fields to solve the problem accurately.
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a three phase transmission line consists of three conductors that are supported at points A,B, c to form an equilateral triangle. At one instant, conductors A and B both carry a current of 75A while conductor C carries a return current of 150 A. Find the force per meter on conductor C at that instant.

heres what it looks like

A
|
|
|-------C
|
|
B


current at A and B is going in, current at C is coming out. Each point is 2 meters apart.

This is the z = 0 plane
im really stuck on this one.
 
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Where are you stuck, what have you tried?

Spit out some equations you think might fit.
 
the only think i can think of is to find the H field about A and B with rho being equal to the distance to C. than use the int(i*dl cross B). do that at A and B ? i don't see how the 150 amp current causes a force at C.
 
The force on a charge due to magnetic field from each wire will be:

F = i\int{B\times dl}

Now you'll want to find the force for wires A and B at point C. Does the current through C affect the magnetic field? How so?
 
since the current at C is twice at the current at A and B than wouldn't that cancel out the magnetic field?
 
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