What is the force that the car exerts on the driver?

  • Thread starter Thread starter smh745
  • Start date Start date
  • Tags Tags
    Car Force
AI Thread Summary
To determine the force exerted by the car on the driver during a collision, the change in momentum must be calculated. The car's initial momentum is derived from its speed of 150 mi/hr, and its final momentum after bouncing back at 30 mi/hr must be considered. The total change in momentum occurs over the 0.1 seconds of contact with the wall. Applying Newton's second law, the average force can be calculated using the formula for force as the rate of change of momentum. This analysis highlights the critical relationship between speed, momentum, and force in collision scenarios.
smh745
Messages
7
Reaction score
0
A car traveling at 150 mi/hr strikes a wall and bounces backwards at 30 mi/hr. If the car is in contact with the wall for 0.1 seconds, what is the force that the car exerts on the driver?
 
Physics news on Phys.org
Hi smh745! :smile:
smh745 said:
A car traveling at 150 mi/hr strikes a wall and bounces backwards at 30 mi/hr. If the car is in contact with the wall for 0.1 seconds, what is the force that the car exerts on the driver?

(i think it means average force)

Hint: use the full version of good ol' Newton's second law … force = rate of change of momentum :wink:
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Would a marble need the same speed as a car at the bottom of a vertical loop?
Replies
7
Views
2K
Force of car pushing on a truck
Replies
25
Views
1K
How much force does a moving car exert on to the road?
Replies
13
Views
3K
Net impulse and what objects exerts force
Replies
4
Views
3K
What is the Average Speed and Acceleration of a Car on a Straight Road?
Replies
45
Views
5K
Car Crash Analysis: Analyzing Friction & Speed
Replies
9
Views
4K
Car turning and centripetal force
Replies
18
Views
2K
Problem on Mechanics (Newton's law of motion)
Replies
4
Views
2K
Calculating Separation of Cars in a Convoy Moving at Max Speed
Replies
4
Views
3K
How to work out this impact force
Replies
17
Views
2K

Hot Threads

Recent Insights

Back
Top