What is the Formula for Calculating Force of Friction on an Inclined Surface?

AI Thread Summary
To calculate the force of friction on an inclined surface, the formula involves determining the weight of the box and its mass. The box, weighing 435 N, has a mass of 44.3 kg when converted using gravity (9.81 m/s²). The parallel force acting on the box is calculated as 280 N using the sine of the incline angle (40 degrees). The net force responsible for the box's acceleration is found to be 11.1 N, leading to a calculated force of friction of 268.9 N. There is a mention of a potential typo in the expected answer, which should be clarified.
Jus' me
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For the question: A 435 n box is sliding down a 40.00 inclined. If the acceleration of the box is 0.250m/s2. Which formula would I use to find just the force of friction? and would I change the Newtons to kilograms?
 
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The mass of the box is m = Fw/g = 435n / 9.81 m/s2 = 44.3 kg.
Is it 40 degrees?
The parallel force Fp = Fw(sin40) = 280n
The net unbalanced force responsible for acceleration is F = m a = 44.3kg (0.25m/s/s) = 11.1n.
If Ff = |Fp| then the box would not accelerate.
The Force of friction, Ff = 280n - 11.1n = 268.9n I think, but correct me if I am wrong.
Thanks.
 
Well, the answer is supposed to be 10 but I think there was probably a typo. :)
thanks so much for your help!
and yes, it was supposed to be 40.0 degrees. :)
 

Thread 'Inclined treadmills and Galilean Invariance'

This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
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