What is the formula for the charge of a charged soap bubble?

AI Thread Summary
To determine the charge of a charged soap bubble, the relevant formula involves the potential and the radius of the bubble. The potential is given as 100V, and the radius is 0.1mm, with a wall thickness of 3.3x10^-8m. The discussion highlights that the wall thickness is negligible compared to the radius, allowing for the assumption that the outside radius remains 0.1mm. This simplification leads to the conclusion that the wall thickness does not significantly affect the calculation of charge. Ultimately, the focus is on rearranging the potential equation to find the charge, confirming that the problem may be designed to test assumptions about negligible dimensions.
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Homework Statement


A soap bubble of radius 0.1mm has a wall thickness of 3.3x10^-8m, and is charged to a potential of 100V. Give a formula for the charge of the bubble.

I know this is probably a really easy question, but I've only ever done problems with spheres of negligible wall thickness, so not sure if the wall makes a difference.
I know the equation for potential, so I could just rearrange that to get get Q.

Any help is appreciated, cheers.
 
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Some malicious profs have a tendency to give you irrelevant data. Did you know that? :biggrin:

Real question is: what is the outside radius? Is it 0.1mm or 0.1mm + 3.3e-8m? The problem as stated doesn't say, but you'll have to make an assumption. Of course, 3.3e-8 << 1e-4.
 
I think the point is that the thickness IS negligible as you say, so I've been trolled by Professor after all, haha. Thanks.
 
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