What is the Frictional Force Acting on a Toy Being Dragged by a Child?

AI Thread Summary
The discussion focuses on calculating the frictional force acting on a toy being dragged by a child. For part (a), it's established that since the toy moves at a constant velocity with a 0.50N applied force, the frictional force must also be 0.50N, as acceleration is zero. In part (b), participants suggest using the equation Vf = Vi + at to determine acceleration, given the initial and final velocities and the time taken. The conversation emphasizes using known values to derive the necessary calculations without needing all variables upfront. Overall, the thread provides guidance on applying fundamental physics equations to solve the problem.
inzektor95
Messages
3
Reaction score
0

Homework Statement



a toy is dragged along a rough floor by a child

(a) when the child applies a force of 0.50N horizontally the velocity is contant at 1.0 m/s. What is the force of friction on the toy?

(b)when the child pulls harder so that the applied force is 1.00N the velocity of the toy increases uniformly to 2.0 m/s in 5.0 seconds. Calculate the acceleration of the block.

(c) find the mass of the toy

Homework Equations



(a) Do I have to use the frictional force equation to find the answer? (Ffric = μ* F norm)

(b) should I use the net force equation? Fnet=M*A

The Attempt at a Solution



(A)I was considering using the frictional force equation to solve the problem but I don´t have all the variables

(B) Velocity v Time graph perhaps?

thanks for the help (I´m a noob in physics)
 
Physics news on Phys.org
welcome to pf!

hi inzektor95! welcome to pf! :smile:
inzektor95 said:
a toy is dragged along a rough floor by a child

(a) when the child applies a force of 0.50N horizontally the velocity is contant at 1.0 m/s. What is the force of friction on the toy?

(b)when the child pulls harder so that the applied force is 1.00N the velocity of the toy increases uniformly to 2.0 m/s in 5.0 seconds. Calculate the acceleration of the block.

(c) find the mass of the toy

(a) Do I have to use the frictional force equation to find the answer? (Ffric = μ* F norm)

nope!

you can find the friction force either from the cause or from the result

from the cause, you would need to know the mass and the coefficient of friction … you don't, so that's out!

from the result, you know the acceleration is zero, so you should be able to find the force of friction from the information given :wink:

for part (b), again you could find the acceleration either from the cause or from the result …

ues the result … you know the initial velocity the final velocity and the time, so use one of the standard constant acceleration equations :wink:
 
Thanks for the quick reply :)

For A

how can i find the force of friction using the information given? do i have to use a specific equation?

acceleration = 0
velocity = 1.0 m/s
force = 0.50N

For part B

Vi (initial)= 1.0 m/s
Vf (final)= 2.0 m/s
T = 5.0 s
A = ?

so in other words, I should use this equation?
Vf = Vi + at

thank you very much tiny-tim! :D
 
hi inzektor95! :smile:
inzektor95 said:
For A

how can i find the force of friction using the information given? do i have to use a specific equation?

acceleration = 0
velocity = 1.0 m/s
force = 0.50N

if the acceleration is 0, what is the net force? :wink:
For part B

Vi (initial)= 1.0 m/s
Vf (final)= 2.0 m/s
T = 5.0 s
A = ?

so in other words, I should use this equation?
Vf = Vi + at

yup! :biggrin:
 
thank you very much tiny tim:smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top