What Is the Fringe Width in Young's Double Slit Experiment with Red Light?

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In a Young's double slit experiment, the fringe width for green light is 0.20 mm, with green light having a wavelength of 5.2 x 10^-7 m and red light at 6.5 x 10^-7 m. To find the fringe width for red light, the ratio of the wavelengths is used, leading to a calculation that suggests the red light fringe width will be larger. The method involves understanding the relationship between wavelength, distance, and the fringe width in the equation nλ = xd/L. The discussion emphasizes the importance of explaining the variables involved in the calculation. Ultimately, the fringe width increases when switching from green to red light due to the longer wavelength.
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Homework Statement


In a Youngs dbl. slit experiment using green light the fringe width was observed to be 0.20mm.if red light replaces green light,what will be the fringe width?


Homework Equations


hmm lambda=ay/d but (no info is given on rest)=/
wavelengths:green=5.2x10^-7m ,red=6.5x10^-7m

The Attempt at a Solution


well i don't know if its correct but i tried to solve it.by dividing the wavelength of of red over greens and i got 1.25m which i multiplied to (2x10^-4) <---- which is the fringe width of green .=/ i totally made it up .sos here =)
 
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