What Is the General Formula for Straight Chain Alkanes?

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The general formula for straight chain alkanes is CnH2n+2, where n indicates the number of carbon atoms. For instance, methane (CH4) corresponds to C1H4, while ethane (C2H6) corresponds to C2H6. This formula is universally applicable to all straight chain alkanes, regardless of their carbon count. Understanding this formula is essential for identifying and classifying alkanes in organic chemistry. The formula effectively captures the relationship between carbon and hydrogen in these compounds.
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One simple question?

What is the general formula for a straight chain alkane? Please
 
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C_nH_{2n+2}
 
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The general formula for a straight chain alkane is CnH2n+2, where n represents the number of carbon atoms in the molecule. For example, methane (CH4) has one carbon atom, so its formula would be C1H4. Ethane (C2H6) has two carbon atoms, so its formula would be C2H6. This formula applies to all straight chain alkanes, regardless of the number of carbon atoms.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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