What is the Generating Function for Bessel Functions?

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SUMMARY

The generating function for Bessel functions Jn(x) is defined as G(x,t) = ∑ from -∞ to ∞ of tn Jn(x) = exp{(x/2)((t - 1/t))}. This function satisfies the differential equation (t + 1/t)G(x,t) = (2t/x)∂G/∂t, derived from the recurrence relation Jn+1(x) + Jn-1(x) = (2n/x)Jn(x). To solve this, one must partially integrate the equation and determine the unknown function of x by ensuring that the coefficient of t^0 equals J0(x).

PREREQUISITES
  • Understanding of Bessel functions, specifically Jn(x)
  • Familiarity with generating functions in mathematical analysis
  • Knowledge of differential equations and their solutions
  • Experience with integration techniques in calculus
NEXT STEPS
  • Study the properties and applications of Bessel functions in mathematical physics
  • Learn about generating functions and their role in combinatorial mathematics
  • Explore differential equations and methods for solving them
  • Investigate recurrence relations and their significance in series expansions
USEFUL FOR

Mathematicians, physicists, and students studying advanced calculus or mathematical analysis, particularly those interested in special functions and their applications in various fields.

Mark Brewer
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Homework Statement


Show that the Bessel functions Jn(x) (where n is an integer) have a very nice generating function, namely,

G(x,t) := ∑ from -∞ to ∞ of tn Jn(x) = exp {(x/2)((t-T1/t))},

Hint. Starting from the recurrence relation

Jn+1(x) + Jn-1(x) = (2n/x)Jn(x),

show that G(x,t) satisfies the differential equation (t+1/t)G(x,t) = (2t/x)∂G/∂t. Partially integrate this equation and fix the unknown function of x by the requirement that the coefficient of t0 be J0(x)

The Attempt at a Solution


This is the setup I have so far. I'm not sure if this is the correct way to go. If it is please let me know so I can continue down the pipe line.

∫xe^((x/2)(t-1/t))∂t = ∫((2t^2)/(t^2)+1)∂G

Any guidance would be helpful.
 
Thank you, Greg. You can bump this post.
 

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