What Is the Induced EMF in a Circular Coil at t = 5 s?

AI Thread Summary
The discussion revolves around calculating the induced EMF in a circular coil with 35 turns and a diameter of 19 cm placed in a time-varying magnetic field. The magnetic field is defined as B(t) = 6t^2 + 6t + 2 T, and the induced EMF is determined using the formula E = -NAB/dt. A participant initially calculated the EMF as 36.12 V but later realized the error may stem from using the diameter instead of the radius for area calculations. The correct approach involves ensuring proper unit conversions and applying the formula accurately, with the derivative of the magnetic field being dB/dt = 12t + 6. The discussion emphasizes the importance of these calculations and confirms that a negative voltage can occur in this context.
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Homework Statement

A circular coil with 35 turns of wire and a diameter of 19 cm is placed in a magnetic field given by B(t) = 6 t^2 + 6 t + 2 T where t is time in seconds. The field is perpendicular to the plane of the coil. What is the induced EMF at t = 5 s?

Homework Equations

E=-d(magnetic flux)/dtime

The Attempt at a Solution


I found E to be 36.12 V but that's wrong. I'm not sure what's wrong. I did E=NAB/time.
 
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Emf is proportional to negative the derivative or rate of change of the magnetic flux with respect to time. The area is constant, thus
V = -NA*dB/dt.
 
I plugged in -36.12 but it's still wrong. Can we have a negative voltage?
 
Could you please tell me where I'm wrong? I have a couple of hours left.
 
dB/dt = 12t + 6; at t = 5s, dB/dt = 66T/s
N = 35 turns
A = pi*r^2...so your problem might be that you're using the diameter of 19cm instead of the radius; also, be sure that you convert the given units to the proper units, so the radius = d/2 = 9.5cm = .095m.
The emf is V = -NA*dB/dt...and you could have a negative voltage.
 
Thank you very much I appreciate it.
 
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