What Is the Initial Speed of a Diver Jumping from a 10m Board?

AI Thread Summary
A diver jumps from a 10-meter board at a 30-degree angle and reaches the water in 2 seconds. The constant acceleration due to gravity is 9.81 m/s². The challenge lies in determining the initial speed, which requires breaking the velocity into horizontal and vertical components. Attempts to apply kinematic equations have been made, but confusion remains regarding the initial velocity. Clarification on how to calculate the vertical component of the initial velocity is needed for a complete solution.
Matt1234
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Homework Statement




A diver jumps from a 10 m high diving board at an angle of 30 deg above horizontal. 2 seconds later the diver reaches water. What is the initial speed of the diver ?

Homework Equations


v = vi + at
s = si + vit +0.5(a)t^2
v^2= Vi^2 + 2 a (s-s0)


The Attempt at a Solution




I tried applying the above equations yet i can't seem to come up with the method. I know Acceleration is constant 9.81 m/s^2. But the initial velocity is throwing me off, i have also tried to break the velocity into components, but was unseccessful.
Thank you.
 
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Matt1234 said:
But the initial velocity is throwing me off, i have also tried to break the velocity into components, but was unseccessful.
Show what you've tried. Hint: If the initial velocity is 'v', what's the vertical component?
 
here is my attempt, I am sorry for the poor handwriting and poor quality scan. Thank you for your help.

[PLAIN]http://img24.imageshack.us/img24/7664/lastscanql.jpg
 
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