What is the intuition behind root mean square?

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Homework Help Overview

The discussion revolves around the concept of root mean square (RMS) and its intuitive understanding, particularly in relation to distance and averages. Participants are exploring how RMS connects to the mean of a set of values and the implications of using absolute values in calculations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the rationale behind dividing the distance by the number of dimensions (n) when calculating RMS. They are exploring the significance of this division in relation to average distance and how it relates to the concept of measuring 'how large' values are.

Discussion Status

The discussion is ongoing, with participants providing insights and raising questions about the definitions and interpretations of RMS. There is an exploration of different ways to define averages, but no consensus has been reached on the significance of dividing by n.

Contextual Notes

Some participants have noted typographical errors in their posts regarding the use of "inverse" and clarified that they meant to refer to absolute values instead. This indicates a focus on precise definitions in the discussion.

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Essentially the root mean square is a distance. If you were to calculate the distance the point (x, y, z) is from (0,0,0) you would calculate \sqrt{x^2+ y^2+ z^2}. The "root mean square" is really an "average distance", thinking of each value in the set as a "dimension".

Of course, that's not the only way to define an "average". Also used is to, not "inverse" every sign since that would mean changing positive to negative, take the arithmetic average of the absolute values:
\frac{|a_1|+ |a_2|+ \cdot\cdot\cdot+ |a_n|}{n}
 
Thanks but why the distance needs to divide by n(in this case n=3)?
ie
\frac{\sqrt{(x^2+ y^2+ z^2)}{n}

Seems like it is the average distance of each dimension in the n-dimension to the original point. Am I right?
If yes, may I know what is the significant value to define it as such?

>>not "inverse" every sign since that would mean changing positive to negative
Sorry typo, it should be taking absolute value as you mentioned:)
 
Last edited:
jack1234 said:
Thanks but why the distance needs to divide by n(in this case n=3)?
ie
\frac{\sqrt{(x^2+ y^2+ z^2)}}{n}

Seems like it is the average distance of each dimension in the n-dimension to the original point. Am I right?
If yes, may I know what is the significant value to define it as such?
When you measure an "average" of a number of things you are, basically, measuring 'how large' they are. A distance measure is a natural analogy to use.

>>not "inverse" every sign since that would mean changing positive to negative
Sorry typo, it should be taking absolute value as you mentioned:)
 

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