What Is the Key Step Missing in Deriving Wirtinger Derivatives?

  • Thread starter Thread starter paraboloid
  • Start date Start date
  • Tags Tags
    Derivatives Derive
paraboloid
Messages
17
Reaction score
0
Let \bar{z} = x+iy.
We are given that x = \frac{z+\bar{z}}{2} & y = \frac{z-\bar{z}}{2i}.

We are trying to derive \partial F/\partial\bar{z} = 1/2(\partial F/ \partial x + i \partial F/ \partial y), where F(x,y) is some function of two real variables.

Using the chain rule I get \partial F/\partial\bar{z} = \partial F/\partial x\cdot\partial x/\partial\bar{z} + \partial F/\partial y\cdot\partial y/\partial\bar{z}.
This is the point where I know something is going wrong.

I replace \partial x/\partial\bar{z} with \partial \frac{z+\bar{z}}{2}/\partial\bar{z}, and the same for y with \frac{z-\bar{z}}{2i}.

Taking the partial derivatives \partial \frac{z+\bar{z}}{2}/\partial\bar{z} & \partial \frac{z-\bar{z}}{2i}/\partial\bar{z},
I get \partial F/\partial\bar{z} = \partial F/\partial x\cdot\frac{1}{2}-\partial F/\partial y\cdot\frac{1}{2i} = \frac{1}{2}(\partial F/\partial x - \partial F/i\partial y).

What key step am I missing that's leading me to the wrong expression?
 
Physics news on Phys.org
paraboloid said:
Let \bar{z} = x+iy.
We are given that x = \frac{z+\bar{z}}{2} & y = \frac{z-\bar{z}}{2i}.

We are trying to derive \partial F/\partial\bar{z} = 1/2(\partial F/ \partial x + i \partial F/ \partial y), where F(x,y) is some function of two real variables.

Using the chain rule I get \partial F/\partial\bar{z} = \partial F/\partial x\cdot\partial x/\partial\bar{z} + \partial F/\partial y\cdot\partial y/\partial\bar{z}.
This is the point where I know something is going wrong.

I replace \partial x/\partial\bar{z} with \partial \frac{z+\bar{z}}{2}/\partial\bar{z}, and the same for y with \frac{z-\bar{z}}{2i}.

Taking the partial derivatives \partial \frac{z+\bar{z}}{2}/\partial\bar{z} & \partial \frac{z-\bar{z}}{2i}/\partial\bar{z},
I get \partial F/\partial\bar{z} = \partial F/\partial x\cdot\frac{1}{2}-\partial F/\partial y\cdot\frac{1}{2i} = \frac{1}{2}(\partial F/\partial x - \partial F/i\partial y).

What key step am I missing that's leading me to the wrong expression?

\frac{1}{2}(\partial F/\partial x - \partial F/i\partial y)= \frac{1}{2}(\partial F/\partial x + i \partial F/\partial y),

so I think you derived the stated result. Incidentally, you have a typo at the top. With the definitions of x and y that you used, \bar{z} = x - i y.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top