What Is the Kinetic Energy of an Alpha Particle at Point B in Electron Volts?

AI Thread Summary
The discussion focuses on calculating the kinetic energy of an alpha particle as it moves from a potential of +240 V to -120 V. The potential difference is determined to be -360 V, which is crucial for finding the kinetic energy. The relationship between electric potential and kinetic energy is highlighted, emphasizing that the energy gained by the particle corresponds to the change in potential multiplied by its charge. The concept of an electron volt is explained, indicating that it represents the energy gained by an electron moving through one volt. The key takeaway is that the kinetic energy of the alpha particle at point B can be calculated using the established potential difference.
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Homework Statement



Point A is at a potential of +240 V, and point B is at a potential of -120 V. An -particle is a helium nucleus that contains two protons and two neutrons;

the neutrons are electrically neutral. An -particle starts from rest at A and accelerates toward B.

When the -particle arrives at B, what kinetic energy (in electron volts) does it have?
in eV

Homework Equations





The Attempt at a Solution



W = q * (chng in V)

q is the charge stored by a dialectric capacitor.

and change in V is the electric potential difference.

chng in V = Vb - Va = -360 V correct?

so where does the q come from?
 
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Let me give you the definition of an "electron volt:"

The energy gained by an electron, in moving through a potential of one volt, is one electron volt.

- Warren
 
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