What is the Kinetic Energy of H-Atom in HBr Photodissociation?

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To solve for the kinetic energy of a hydrogen atom during the photodissociation of HBr molecules, one can use Einstein's equation E=hv=hc/λ, where E represents the total energy. The total energy is the sum of the dissociation energy and the kinetic energy of the hydrogen atom. By rearranging the equation, the kinetic energy can be determined once the dissociation energy and the wavelength of the photons are known. However, the discussion raises a question about the conditions under which this calculation is valid, specifically regarding temperature and pressure, indicating that these factors may influence the results.
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Hi yall! Does anyone know how one can solve kinetíc energy of H-atom if the dissociation energy and the wavelenght of photons are known when HBr-molecules are photodissociated? Tricky... :cry:
 
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I'll take a stab at this. You know by Einstein's equation E=hv=hc/Lamda.


E=dissociation energy+kinetic energy. You can find E and you are given dissociation energy, solve for kinetic energy.


Again, I am not 100% sure if this is correct.
 
At what temperature and pressure ?
 

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